document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=204103>Question 204103</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The width of a rectangle is 15ft. less that its length, and the perimeter is 210 ft. Find the width? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #154051 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=154051\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter =210 =2l +2w,,,but  w=l-15,,,<BR>\n" );
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document.write( "210 = 2l +2(l-15)<BR>\n" );
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document.write( "210 =2l + 2l -30<BR>\n" );
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document.write( "240 = 4l<BR>\n" );
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document.write( "60 = l,,,,,w= l-15 =60-15 = 45<BR>\n" );
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document.write( "check per=210= 2*60 +2*45 = 120 +90,,,,,,ok<BR>\n" );
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