document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=204104>Question 204104</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Could someone please help me out? I got this far and now am lost.....\r<BR>\n" );
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document.write( "A rope is stretched from the ground to the top of a tower. The wire is 10 ft. long. The height is 2 ft greater than the distance from the towers base to the end of the wire. Find the distance &height.\r<BR>\n" );
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document.write( "r(r+10)=2<BR>\n" );
document.write( "r(r+10)-2=0<BR>\n" );
document.write( "(r-  )(r+  )    not sure??????? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #154047 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=154047\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the rope/wire is the hypotenuse of a right triangle formed by the rope/wire, the tower, and the base distance\r<BR>\n" );
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document.write( "let x=\"base distance\", so x+2=\"tower height\"\r<BR>\n" );
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document.write( "by Pythagoras, x^2 + (x+2)^2 = 10^2 ___ x^2 + x^2 + 4x + 4 = 100 ___ x^2 + 2x +2 = 50\r<BR>\n" );
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document.write( "x^2 + 2x - 48 = 0 ___ factoring ___ (x+8)(x-6) = 0 ___ so, x = 6 and x+2 = 8 </SPAN>\n" );
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