document.write( "Question 204081: Can someone help me solve this word problem?\r
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document.write( "The Hudson River flows at a rate of 5 miles per hour. A patrol boat travels 40 miles upriver, and returns in a total time of 6 hrs. What is the speed of the boat in still water? \n" );
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Algebra.Com's Answer #154026 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The Hudson River flows at a rate of 5 miles per hour. A patrol boat travels 40 miles upriver, and returns in a total time of 6 hrs. What is the speed of the boat in still water? \n" ); document.write( "-------------------------- \n" ); document.write( "Upriver DATA: \n" ); document.write( "distance = 40 miles ; rate = b-5 ; time = d/r = 40/(b-5) hrs. \n" ); document.write( "-------------------------- \n" ); document.write( "Downriver DATA: \n" ); document.write( "distance = 40 miles ; rate = b+5 ; time = 40/(b+5) hrs \n" ); document.write( "--------------------------- \n" ); document.write( "Equation: \n" ); document.write( "time up + time down = 6 hrs \n" ); document.write( "--- \n" ); document.write( "40/(b-5) + 40/(b+5) = 6 \n" ); document.write( "--- \n" ); document.write( "Multiply thru by (b-5)(b+5) to get: \n" ); document.write( "40(b+5) + 40(b-5) = 6(b^2-25) \n" ); document.write( "80b = 6b^2 - 150 \n" ); document.write( "6b^2 - 80b - 150 = 0 \n" ); document.write( "3b^2 - 40b - 75 = 0 \n" ); document.write( "(b-15)(3b+5) = 0 \n" ); document.write( "Positive solution: \n" ); document.write( "b = 15 mph (speed of the boat in still water) \n" ); document.write( "=============================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |