document.write( "Question 204057: Two corresponding sides of similar polygons are in the ratio of 2: 3. If the perimeter of the smaller figure is 6 meters, what is the perimeter of the larger figure?\r
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Algebra.Com's Answer #154008 by feliz1965(151) $\"\"$ $\"About$

You can put this solution on YOUR website!
I believe the proportion you want is this one:\r
\n" ); document.write( "\n" ); document.write( "2/3 = 6/x\r
\n" ); document.write( "\n" ); document.write( "Let x = perimeter of larger figure\r
\n" ); document.write( "\n" ); document.write( "Can you solve for x now?\r
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\n" ); document.write( "\n" ); document.write( "I got your reply. Here is mine.\r
\n" ); document.write( "\n" ); document.write( "2/3 = 6 meters/x meters\r
\n" ); document.write( "\n" ); document.write( "You got x = 9.\r
\n" ); document.write( "\n" ); document.write( "Let's see if that's correct.\r
\n" ); document.write( "\n" ); document.write( "Replace x with 9 and reduce the right side fraction.\r
\n" ); document.write( "\n" ); document.write( "2/3 = 6 meters/9 meters\r
\n" ); document.write( "\n" ); document.write( "2/3 = 2/3...It checks!\r
\n" ); document.write( "\n" ); document.write( "So, the larger perimeter is 9 meters.\r
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