document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=204047>Question 204047</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi all, I was hoping someone could help with the following; I need to <BR>\n" );
document.write( "Solve this cubic equation for x: x^3 - 4x^2 + x + 6 = 0.<BR>\n" );
document.write( "Any help would be great,<BR>\n" );
document.write( "Thanks.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #153987 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=153987\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^3 - 4x^2 + x + 6 = 0<BR>\n" );
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document.write( "If you substitute x = -1 you will see that -1 is a root.<BR>\n" );
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document.write( "Using synthetic division you can find the other roots.<BR>\n" );
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document.write( "-1)....1....-4....1....6<BR>\n" );
document.write( ".........1.....-5...6...|..0\r<BR>\n" );
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document.write( "Quotient: x^2-5x+6<BR>\n" );
document.write( "Factor: (x-3)(x-2) = 0<BR>\n" );
document.write( "Ans: x = -1 or 2 or 3<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );