document.write( "Question 28317: The speed of a stream is 4 mph. If a boat travels 52 miles downstream in the same time that it takes to travel 26 miles upstream, what is the speed on the boat in still water? \n" ); document.write( "
Algebra.Com's Answer #15391 by josmiceli(19441)\"\" \"About 
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The thing that stays the same for both trips is elapsed time\r
\n" ); document.write( "\n" ); document.write( "Solve the rate formula for t
\n" ); document.write( "time = distance / rate
\n" ); document.write( "The times are equal, so
\n" ); document.write( "\"distance%5B1%5D+%2F+rate%5B1%5D+=+distance%5B2%5D+%2F+rate%5B2%5D\"
\n" ); document.write( "The rate for downstream is the rate in still water + rate of the current
\n" ); document.write( "The rate for upstream is the rate in still water - rate of the current
\n" ); document.write( "Fill in the values
\n" ); document.write( "Call the rate in still water r
\n" ); document.write( "\"52+%2F+%28r+%2B+4%29+=+26+%2F+%28r+-+4%29\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "\"26%2Ar+%2B+104+=+52%2Ar+-+208\"
\n" ); document.write( "\"26%2Ar+=+312\"
\n" ); document.write( "\"r+=+12\"
\n" ); document.write( "So, the speed in still water is 12 mph
\n" ); document.write( "Check by plugging into equation
\n" ); document.write( "\"52+%2F+%2812+%2B+4%29+=+26+%2F+%2812+-+4%29\"
\n" ); document.write( "\"52+%2F+16+=+26+%2F+8\"
\n" ); document.write( "\"13%2F4+=+13%2F4\"
\n" ); document.write( "Checks
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