document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=203992>Question 203992</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Q- Find the angle whose complementry angle is 18 more.\r<BR>\n" );
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document.write( "A:- is 54  but how??? plz explain.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #153908 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=153908\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if an angle is x degrees, then its complementary angle is 90-x because the sum of the angle and its complementary angle must equal 90 degrees.<BR>\n" );
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document.write( "your problem asks to find the angle who complementary angle is 18 degrees more than the angle.<BR>\n" );
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document.write( "let your angle = x <BR>\n" );
document.write( "let your complementary angle = x+18<BR>\n" );
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document.write( "since an angle and its complementary angle must equal 90 degrees, your equation is:<BR>\n" );
document.write( "x + (x + 18) = 90<BR>\n" );
document.write( "remove parentheses to get x + x + 18 which is the same as 2x + 18 = 90<BR>\n" );
document.write( "subtract 18 from both sides of this equation and you get 2x = 72<BR>\n" );
document.write( "divide both sides of this equation by 2 and you get x = 36<BR>\n" );
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document.write( "your angle is 36 degrees<BR>\n" );
document.write( "your complementary angle is 36 + 18 = 54 degrees<BR>\n" );
document.write( "54 + 36 = 90<BR>\n" );
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