document.write( "Question 203841: Jean goes to a movie theater where a ticket costs $7 and any snack item-candy,popcorn,or drink-sells for $1.50 each. Frank goes to a theater where the ticket costs $4 and candy, popcorn, or drinks sell for $2.50 each. How many snack items would jean and Frank need to buy, so that they each pay the same amount at the theater? \n" ); document.write( "
Algebra.Com's Answer #153880 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Jean goes to a movie theater where a ticket costs $7 and any snack \n" ); document.write( " item-candy,popcorn,or drink-sells for $1.50 each. \n" ); document.write( "Frank goes to a theater where the ticket costs $4 and candy, popcorn, \n" ); document.write( " or drinks sell for $2.50 each. \n" ); document.write( "How many snack items would jean and Frank need to buy, so that they \n" ); document.write( " each pay the same amount at the theater? \n" ); document.write( ": \n" ); document.write( "Let n = number of snack items bought for equal amts \n" ); document.write( ": \n" ); document.write( "Franks$ = Jeans% \n" ); document.write( " 2.50n + 4 = 1.50n + 7 \n" ); document.write( "2.5n - 1.5n = 7 - 4 \n" ); document.write( "n = 3 snack items \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution in original equation \n" ); document.write( "2.5(3) + 4 = 1.5(3) + 7 \n" ); document.write( "7.50 + 4 = 4.50 + 7 \n" ); document.write( " |