document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=203927>Question 203927</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please could you help me with this question?\r<BR>\n" );
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document.write( "Find an equation for which -3 and 4 are solutions. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #153856 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=153856\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find an equation for which -3 and 4 are solutions.<BR>\n" );
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document.write( "Remember when you \"factored\" a quadratic and it would give you two solutions?<BR>\n" );
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document.write( "This is sort of a \"reverse\" process.<BR>\n" );
document.write( "If -3 and 4 are solutions, then:<BR>\n" );
document.write( "(x+3) and (x-4)<BR>\n" );
document.write( "MUST be factors.<BR>\n" );
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document.write( "Now, to find an equation -- multiply the two factors together:<BR>\n" );
document.write( "(x+3)(x-4)<BR>\n" );
document.write( "FOIL:<BR>\n" );
document.write( "x^2 - 4x + 3x - 12<BR>\n" );
document.write( "Combine like-terms:<BR>\n" );
document.write( "x^2 - x - 12 = 0  (this is what they're looking for)<BR>\n" );
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