document.write( "Question 203863: help needed:
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document.write( "Give points which are outside and pont which are inside of the circles in this equation: x^2+y^2+6x=0
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document.write( "p.s: could you please explain the solution for me that I can solve a group of questions like this ? Thank you:) \n" );
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Algebra.Com's Answer #153818 by Alan3354(69443) You can put this solution on YOUR website! Give points which are outside and pont which are inside of the circles in this equation: x^2+y^2+6x=0 \n" ); document.write( "------------------ \n" ); document.write( "You need to find the center and the radius of the circle. \n" ); document.write( "Put it into standard form, \n" ); document.write( "(x-h)^2 + (y-k)^2 = r^2 where the center is at (h,k) and the radius is r. \n" ); document.write( "x^2+y^2+6x=0 \n" ); document.write( "Complete the square for the x terms. \n" ); document.write( "x^2 + 6x + 9 + y^2 = 9 \n" ); document.write( "(x+3)^2 + y^2 = 3^2 \n" ); document.write( "So the center is (-3,0) and the radius is 3. \n" ); document.write( "---------------------------- \n" ); document.write( "Assuming you mean all points inside and out: \n" ); document.write( "Inside: \n" ); document.write( "(x+3)^2 + y^2 <9 \n" ); document.write( "Outside: \n" ); document.write( "(x+3)^2 + y^2 >9 \n" ); document.write( "------------------ \n" ); document.write( "That's it. This one could have been shortcutted, but that might not apply in all cases. Changing the = to < and > might move the center of the circle. \n" ); document.write( " |