document.write( "Question 203857: Please help me about this :
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document.write( "Find R so that the circle x^2+y^2=R^2 is tangent to the line x+2y=4.
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document.write( "Thanx:) \n" );
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Algebra.Com's Answer #153812 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Find R so that the circle x^2+y^2=R^2 is tangent to the line x+2y=4. \n" ); document.write( "-------------------- \n" ); document.write( "The center of the circle is the Origin. A line from the center to the tangent point will be perpendicular to the line x+2y=4. See that? Since it's perpendicular, its slope will be the negative inverse of the line, and it passes thru the origin. \n" ); document.write( "------------- \n" ); document.write( "Find the slope of x+2y=4 by putting it into slope-intercept form (that means solve for y). \n" ); document.write( "y = (-1/2)x + 2 so the slope, m, is -1/2. \n" ); document.write( "The slope of the line from the center, the Origin, to the tangent point will have a slope of +2. \n" ); document.write( "------------ \n" ); document.write( "Use y-y1 = m*(x-x1) to find the eqn of the radial line. \n" ); document.write( "y = 2x since the point is (0,0) \n" ); document.write( "---------------------- \n" ); document.write( "Now solve the pair of eqns to find the tangent point. \n" ); document.write( "x + 2y = 4 \n" ); document.write( "y = 2x \n" ); document.write( "x + 2*(2x) = 4 \n" ); document.write( "5x = 4 \n" ); document.write( "x = 0.8 \n" ); document.write( "y = 1.6 \n" ); document.write( "The tangent point is (0.8,1.6). \n" ); document.write( "The radius, R, is the distance from the Origin to the point. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "R = sqrt(3.2) = 4*sqrt(5)/5 \n" ); document.write( " \n" ); document.write( " |