document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=203867>Question 203867</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the inspection division of a county weifhts and measures department wants to estimate the mean amount of soft-drink fill in 2-liter bottles to with +/- 0.01 liter with 95% confidence and also assumes that the standard deviation is 0.05 liter, what sample size is needed? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #153805 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=153805\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the inspection division of a county weights and measures department wants to estimate the mean amount of soft-drink fill in 2-liter bottles to within +/- 0.01 liter with 95% confidence and also assumes that the standard deviation is 0.05 liter, what sample size is needed?<BR>\n" );
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document.write( "Since E = z<BR>\n" );
document.write( "sqrt(n) = z<BR>\n" );
document.write( "n = [z*s/E]^2<BR>\n" );
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document.write( "Your Problem:<BR>\n" );
document.write( "n = [1.96*0.05/0.01]^2<BR>\n" );
document.write( "n = 96.04<BR>\n" );
document.write( "Rounding up you get n = 97 (this is the required sample size)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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