document.write( "Question 203793: I am so confused on (ln) & (logs) & (e)....\r
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document.write( "problem\r
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document.write( "10^(t^2-t)=100\r
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document.write( "what does this mean? and how do i solve? \n" );
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Algebra.Com's Answer #153794 by RAY100(1637) ![]() You can put this solution on YOUR website! 10^(t^2-t) = 100 = 10^2 \n" ); document.write( ". \n" ); document.write( "This can be solved without logs by setting exponents equal \n" ); document.write( ". \n" ); document.write( "t^2-t=2 \n" ); document.write( ". \n" ); document.write( "t^2 -t -2 =0 \n" ); document.write( ". \n" ); document.write( "(t-2)(t+1) =0 \n" ); document.write( ". \n" ); document.write( "t= 2, -1 \n" ); document.write( ". \n" ); document.write( "check \n" ); document.write( "(t=2),,10^2 = 100,,,,ok \n" ); document.write( "(t=-1),,,,10^2 = 100,,,,ok \n" ); document.write( " |