document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=28302>Question 28302</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have an equation for a circle (x+3)^2+(y-1)^2=25 where the centre point is 3,1 and th radius is 5. I need to show that the line of equation y=-x-1 intercepts the circle. I have substituted the value of y into the circle<BR>\n" );
document.write( "(x+3)^2+(-x-1-1)^2=25 <BR>\n" );
document.write( "(x+3)^2+(-x-2)^2=25 <BR>\n" );
document.write( "But how do i get from here to 2x^2+10x-12=0 an then show that the line intercepts? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #15379 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=15379\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+%28x%2B3%29%5E2%2B%28-x-2%29%5E2=25+ ALIGN=MIDDLE  ALT=\"+%28x%2B3%29%5E2%2B%28-x-2%29%5E2=25+\"   DISABLED_style= \"max-width:90%; height:auto;\" > is fine so far. And where do you get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+2x%5E2%2B10x-12=0+ ALIGN=MIDDLE  ALT=\"+2x%5E2%2B10x-12=0+\"   DISABLED_style= \"max-width:90%; height:auto;\" > from? How do you know that is the quadratic you are aiming for? :-)\r<BR>\n" );
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document.write( "Anyway, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+%28x%2B3%29%5E2%2B%28-x-2%29%5E2=25+ ALIGN=MIDDLE  ALT=\"+%28x%2B3%29%5E2%2B%28-x-2%29%5E2=25+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+x%5E2+%2B+6x+%2B+9+%2B+x%5E2+%2B+4x+%2B+4+=+25+ ALIGN=MIDDLE  ALT=\"+x%5E2+%2B+6x+%2B+9+%2B+x%5E2+%2B+4x+%2B+4+=+25+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+2x%5E2+%2B+6x+%2B+9+%2B+4x+%2B+4+=+25+ ALIGN=MIDDLE  ALT=\"+2x%5E2+%2B+6x+%2B+9+%2B+4x+%2B+4+=+25+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+2x%5E2+%2B+10x+%2B+9+%2B+4+=+25+ ALIGN=MIDDLE  ALT=\"+2x%5E2+%2B+10x+%2B+9+%2B+4+=+25+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+2x%5E2+%2B+10x+%2B+13+=+25+ ALIGN=MIDDLE  ALT=\"+2x%5E2+%2B+10x+%2B+13+=+25+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+2x%5E2+%2B+10x+-+12+=+0+ ALIGN=MIDDLE  ALT=\"+2x%5E2+%2B+10x+-+12+=+0+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+x%5E2+%2B+5x+-+6+=+0+ ALIGN=MIDDLE  ALT=\"+x%5E2+%2B+5x+-+6+=+0+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "(x+6)(x-1) = 0\r<BR>\n" );
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document.write( "so x+6=0 OR x-1=0<BR>\n" );
document.write( "--> x=-6 OR x=1\r<BR>\n" );
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document.write( "This says there are 2 solutions of the \"circle\" and the \"line\" ie where they are EQUAL ie where they intersect.\r<BR>\n" );
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document.write( "I have told you their x-coordinates. If you need to quote the y values....find them too, from y=-x-1... easiest equation to use.\r<BR>\n" );
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document.write( "jon.<BR>\n" );
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