document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=203783>Question 203783</A>: <I><SPAN STYLE=\"word-break: break-all;\"> ok. i have never understood logarithmic equations<BR>\n" );
document.write( "do u mind helping?\r<BR>\n" );
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document.write( "4log(1-5x)= 2\r<BR>\n" );
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document.write( "i remeber having to do somthing like puting a 4 after log and it cancels and moves to the 2... something like that... can u show me the steps on how to solve logarithms :-]  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #153771 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=153771\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> remember  def  of  log,,,log(10)a=b if  and  only  if 10^b =a<BR>\n" );
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document.write( "and  log a^b =b*log a<BR>\n" );
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document.write( "4 log(1-5x) = 2<BR>\n" );
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document.write( "log (1-5x)^4 =2<BR>\n" );
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document.write( "10^2 =(1-5x)^4<BR>\n" );
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document.write( "100 = (1-5x)^4<BR>\n" );
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document.write( "taking  4th  power  of  both  sides,,<BR>\n" );
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document.write( "(100)^(1/4) = 3.162 = (1-5x)<BR>\n" );
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document.write( "3.162 -1 = 2.162 = -5x<BR>\n" );
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document.write( "x= -.4325<BR>\n" );
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document.write( "checking<BR>\n" );
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document.write( "4 log(1-5x) =2<BR>\n" );
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document.write( "4 log (1-5(-.4325) ) =2<BR>\n" );
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document.write( "4log(3.162) =2<BR>\n" );
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document.write( "4*.5 =2<BR>\n" );
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document.write( "2=2,,,,,ok </SPAN>\n" );
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