document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=203784>Question 203784</A>: <I><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "i have this problem\r<BR>\n" );
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document.write( "2e^(4x-2)=9\r<BR>\n" );
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document.write( "i know that i can use the calculator to find (e) but what about x?\r<BR>\n" );
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document.write( "thank you in advance! :-] </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #153763 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=153763\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You must apply \"log rules\":<BR>\n" );
document.write( "2e^(4x-2)=9<BR>\n" );
document.write( "e^(4x-2) = 9/2<BR>\n" );
document.write( "Take the natural ln of both sides:<BR>\n" );
document.write( "4x - 2 = ln(9/2)<BR>\n" );
document.write( "4x = ln(9/2) + 2<BR>\n" );
document.write( "x = [ln(9/2) + 2]/4<BR>\n" );
document.write( "x = 0.876 </SPAN>\n" );
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