document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=203774>Question 203774</A>: <I><SPAN STYLE=\"word-break: break-all;\"> This will use distance velocity and time and will require 2 equations\r<BR>\n" );
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document.write( "I bicycle at 20 mph and leave the starting point at 8 AM\r<BR>\n" );
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document.write( "My buddy drives at 40 mph and leaves the starting point at 10 AM following me\r<BR>\n" );
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document.write( "How far have I gone when he catches up and how much time has passed\r<BR>\n" );
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document.write( "I got the answer as, I will have traveled 80 miles and 4 hours will have passed, but I would like to see it in a formula, so I can understand the algebra formula<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #153758 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=153758\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if your time is T, then your buddy's time is T-2 (two hours less)<BR>\n" );
document.write( "you know the rates<BR>\n" );
document.write( "when he catches up, you both will have travelled an EQUAL distance<BR>\n" );
document.write( "d = r * t\r<BR>\n" );
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document.write( "20 * T = 40 * (T - 2) ___ 20T = 40T - 80 ___ -20T = -80 ___ T = 4\r<BR>\n" );
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document.write( "substituting back to find distance ___ d = 20 * 4 ___ d = 80 </SPAN>\n" );
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