document.write( "Question 203754: Rosita's Christmas present from Calos is in a box that has a width that is 3 in shorter than the height. the length of the base is 5in longer than the height. If the area of the base is 84 square inches then what is the height of the package? \n" ); document.write( "
Algebra.Com's Answer #153752 by Earlsdon(6294)\"\" \"About 
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Given:
\n" ); document.write( "\"W+=+%28h-3%29\"
\n" ); document.write( "\"L+=+%28h%2B5%29\"
\n" ); document.write( "The area of the base is found by:
\n" ); document.write( "\"A+=+L%2AW\" Substitute from above:
\n" ); document.write( "\"A+=+%28h%2B5%29%2A%28h-3%29\" Substitute A = 84 sq.in.
\n" ); document.write( "\"84+=+h%5E2%2B2h-15\" Subtract 84 from both sides.
\n" ); document.write( "\"h%5E2%2B2h-99+=+0\" Factor the left side.
\n" ); document.write( "\"%28h-9%29%28h%2B11%29+=+0\" Apply the zero product rule. If \"a%2Ab+=+0\" then \"a+=+0\" or \"b+=+0\" or both.
\n" ); document.write( "\"h-9+=+0\" or \"h%2B11+=+0\" so that:
\n" ); document.write( "\"h+=+9\" or \"cross%28h+=+-11%29\" Discard the negative solution as height is a positive quantity.
\n" ); document.write( "\"h+=+9\"
\n" ); document.write( "The height of the package is 9 inches.
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