document.write( "Question 203715This question is from textbook College Algebra
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document.write( ": Identify the vertex and intercepts of the graph f y=x^2+4x+3 \n" );
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Algebra.Com's Answer #153719 by tina_wood(5)![]() ![]() ![]() You can put this solution on YOUR website! f(x)= x^2+4x+3\r \n" ); document.write( "\n" ); document.write( "to find the vertex, use (-b/2a)\r \n" ); document.write( "\n" ); document.write( "-4/2(1) = -4/2 = -2 This is the x part of the vertex (-2,?), then we use -2 in place of x in f(x)\r \n" ); document.write( "\n" ); document.write( "f(-2) = (-2)^2+4(-2)+3 \n" ); document.write( " = 4-8+3 \n" ); document.write( " = -1\r \n" ); document.write( "\n" ); document.write( "Therefore the vertex is (-2,-1)\r \n" ); document.write( "\n" ); document.write( "To find the x - intercepts, you set the equation to equal 0\r \n" ); document.write( "\n" ); document.write( "x^2+4x+3=0 (does it factor?)\r \n" ); document.write( "\n" ); document.write( "(x+3)=0, (x+1)=0 \n" ); document.write( " x= -3, x=-1\r \n" ); document.write( "\n" ); document.write( "To find the y-intercepts, let x=0\r \n" ); document.write( "\n" ); document.write( "x^2+4x+3 \n" ); document.write( "(0)^2+4(0)+3\r \n" ); document.write( "\n" ); document.write( "y=3 \n" ); document.write( " \n" ); document.write( " |