document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=203725>Question 203725</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2x+y=3,y=4<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #153715 by </B><A HREF=/tutors/aboutme.mpl?userid=tina_wood><B>tina_wood(5)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tina_wood><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=153715\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x+y=3,y=4<BR>\n" );
document.write( "Replace the y in the equation with 4 (2x+4=3),then you solve to find out what x is. The next step is to subtract the 4 from both sides (2x = -1) then divide both sides by 2 to solve for x (x = -1/2). To check your equation, put the values for x and y into your equation to see if it equals out:\r<BR>\n" );
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document.write( "2x+y=3<BR>\n" );
document.write( "2(-1/2)+4=3<BR>\n" );
document.write( "(-1)+4=3<BR>\n" );
document.write( "3=3 </SPAN>\n" );
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