document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=203707>Question 203707</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The current I in an electrical conductor varies inversely as the resistance R of the conductor. The current is 3 amperes when the resistance is 960 ohms. What is the current when the resistance is 540 ohms? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #153693 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=153693\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use Ohm's law or a ratio.<BR>\n" );
document.write( "E=ir<BR>\n" );
document.write( "E=3*960<BR>\n" );
document.write( "E=2880<BR>\n" );
document.write( "--------------<BR>\n" );
document.write( "i=E/r<BR>\n" );
document.write( "i=2880/960<BR>\n" );
document.write( "i=5.3 amps </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );