document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=203699>Question 203699</A>: <I><SPAN STYLE=\"word-break: break-all;\"> can u please help\r<BR>\n" );
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document.write( "If the ratio of two supplementary angles is 7 to 8, calculate the measure of the larger of the two angles. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #153685 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=153685\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Supplemental  means  that  the  sum  of  the  2  angles  is  180 degrees<BR>\n" );
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document.write( "If  one  angle  is  \"x\" ,,,the  other  angle  is \"180-x\"<BR>\n" );
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document.write( "ratio = x/(180-x) = 7/8<BR>\n" );
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document.write( "cross  multiply<BR>\n" );
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document.write( "8x = 7*180 - 7x<BR>\n" );
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document.write( "15x = 1260<BR>\n" );
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document.write( "x= 84<BR>\n" );
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document.write( "(180-x) = 180-84 = 96<BR>\n" );
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document.write( "check,,ratio 84/96 = 7/8,,,,ok<BR>\n" );
document.write( ",,,,,96 - 84 = 180,,,ok </SPAN>\n" );
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