document.write( "Question 203665: Angela needs 20 quarts of 50%
\n" ); document.write( " antifreeze solution in her radiator. She plans to obtain this
\n" ); document.write( " by mixing some pure antifreeze with an appropriate
\n" ); document.write( " amount of a 40% antifreeze solution. How many quarts of
\n" ); document.write( " each should she use?
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Algebra.Com's Answer #153669 by ankor@dixie-net.com(22740)\"\" \"About 
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needs 20 quarts of 50% antifreeze solution in her radiator.
\n" ); document.write( "plans to obtain this by mixing some pure antifreeze with an appropriate
\n" ); document.write( " amount of a 40% antifreeze solution. How many quarts of antifreeze?
\n" ); document.write( ":
\n" ); document.write( "Let x = amt of pure antifreeze
\n" ); document.write( "The resulting amt is to be 20 qts, therefore
\n" ); document.write( "(20-x) = amt of 40% solution required
\n" ); document.write( ":
\n" ); document.write( "A typical mixture problem
\n" ); document.write( ":
\n" ); document.write( "x + .40(20-x) = .50(20)
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\n" ); document.write( "x + 8 - .4x = 10
\n" ); document.write( ":
\n" ); document.write( "x - .4x = 10 - 8
\n" ); document.write( ":
\n" ); document.write( ".6x = 2
\n" ); document.write( "x = \"2%2F.6\"
\n" ); document.write( "x = 3\"1%2F3\" qts of pure anti-freeze
\n" ); document.write( "and
\n" ); document.write( "20 - 3\"1%2F3\" = 16\"2%2F3\" qts of 40% mixture
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