document.write( "Question 203665: Angela needs 20 quarts of 50%
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document.write( " antifreeze solution in her radiator. She plans to obtain this
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document.write( " by mixing some pure antifreeze with an appropriate
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document.write( " amount of a 40% antifreeze solution. How many quarts of
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document.write( " each should she use?
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Algebra.Com's Answer #153669 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! needs 20 quarts of 50% antifreeze solution in her radiator. \n" ); document.write( "plans to obtain this by mixing some pure antifreeze with an appropriate \n" ); document.write( " amount of a 40% antifreeze solution. How many quarts of antifreeze? \n" ); document.write( ": \n" ); document.write( "Let x = amt of pure antifreeze \n" ); document.write( "The resulting amt is to be 20 qts, therefore \n" ); document.write( "(20-x) = amt of 40% solution required \n" ); document.write( ": \n" ); document.write( "A typical mixture problem \n" ); document.write( ": \n" ); document.write( "x + .40(20-x) = .50(20) \n" ); document.write( "; \n" ); document.write( "x + 8 - .4x = 10 \n" ); document.write( ": \n" ); document.write( "x - .4x = 10 - 8 \n" ); document.write( ": \n" ); document.write( ".6x = 2 \n" ); document.write( "x = \n" ); document.write( "x = 3 \n" ); document.write( "and \n" ); document.write( "20 - 3 |