document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=28201>Question 28201</A>: <I><SPAN STYLE=\"word-break: break-all;\"> GOOD AFTERNOON I AM HAVING TROUBLE SOLVING THIS WORD PROBLEM:THE PROBLEM IS:\r<BR>\n" );
document.write( "\n" );
document.write( "A CHEMIST HAS 4 LITERS OF A SOLUTION THAT IS 75% ACETIC ACID. HOW MUCH WATER MUST BE ADDED TO MAKE THE RESULTING SOLUTION 60% ACETIC ACID.\r<BR>\n" );
document.write( "\n" );
document.write( "THANK YOU FOR YOUR HELP. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #15366 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=15366\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4(0.75)=0.6(x+4)<BR>\n" );
document.write( "3=0.6x+2.4<BR>\n" );
document.write( "0.6x=0.6<BR>\n" );
document.write( "x=1\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Hence, about 1 L of water should be added.<BR>\n" );
document.write( "Paul. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );