document.write( "Question 203639: What three techniques can be used to solve a quadratic equation, demonstrate each using x^2-10x-39=0 \n" ); document.write( "
Algebra.Com's Answer #153641 by nerdybill(7384)\"\" \"About 
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To solve:
\n" ); document.write( "x^2-10x-39=0
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\n" ); document.write( "Three techniques could be:
\n" ); document.write( "1. factoring
\n" ); document.write( "2. completing the square
\n" ); document.write( "3. quadratic equation
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\n" ); document.write( "Three techniques could be:
\n" ); document.write( "1. factoring
\n" ); document.write( "x^2-10x-39=0
\n" ); document.write( "(x-13)(x+3)=0
\n" ); document.write( "x = {-3, 13}
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\n" ); document.write( "2. completing the square
\n" ); document.write( "x^2-10x-39=0
\n" ); document.write( "x^2-10x = 39
\n" ); document.write( "x^2-10x+25 = 39+25
\n" ); document.write( "(x-5)^2 = 64
\n" ); document.write( "(x-5) = sqrt(64)
\n" ); document.write( "x-5 = +-(8)
\n" ); document.write( "x = +-(8)+5
\n" ); document.write( "x = {-3, 13}
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\n" ); document.write( "3. quadratic equation
\n" ); document.write( "x^2-10x-39=0
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B-10x%2B-39+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-10%29%5E2-4%2A1%2A-39=256\".
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\n" ); document.write( " Discriminant d=256 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--10%2B-sqrt%28+256+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%28-10%29%2Bsqrt%28+256+%29%29%2F2%5C1+=+13\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%28-10%29-sqrt%28+256+%29%29%2F2%5C1+=+-3\"
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\n" ); document.write( " Quadratic expression \"1x%5E2%2B-10x%2B-39\" can be factored:
\n" ); document.write( " \"1x%5E2%2B-10x%2B-39+=+1%28x-13%29%2A%28x--3%29\"
\n" ); document.write( " Again, the answer is: 13, -3.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-10%2Ax%2B-39+%29\"
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