document.write( "Question 203632: Invest 40,000.00 for one year at 10% interest and 8% interest. $3360 for interest total. What was the amount of interest for each rate? \n" ); document.write( "
Algebra.Com's Answer #153637 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Invest 40,000.00 for one year at 10% interest and 8% interest. $3360 for interest total. What was the amount of interest for each rate?
\n" ); document.write( "-------------------
\n" ); document.write( "Total;;;;;;;: x + y = 40000
\n" ); document.write( "Interest: 0.10x+0.08y = 3300
\n" ); document.write( "-----------------------------------
\n" ); document.write( "Multiply thru 1st by 0.1 to get:
\n" ); document.write( "0.10x + 0.10y = 4000
\n" ); document.write( "-----------
\n" ); document.write( "Subtract that from the \"Interest\" equation:
\n" ); document.write( "-0.02y = -700
\n" ); document.write( "y = $35000 (amount invested at 8%
\n" ); document.write( "Interest at this rate was $2800\r
\n" ); document.write( "\n" ); document.write( "----------------
\n" ); document.write( "Then x = $5000 (amount invested at 10%)
\n" ); document.write( "Interest at this rate was $500
\n" ); document.write( "============================================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );