document.write( "Question 203604: Please someone help me about this :
\n" ); document.write( "Find the point of the intersection of the line y=x+2 and the circle (x-1)^2 + y^2=16
\n" ); document.write( "I guess i should find a point on the line which has distance 4 unit from the centre of the circle that is (1,o) but i don't know how! \n" ); document.write( "
Algebra.Com's Answer #153625 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Find the point of the intersection of the line y=x+2 and the circle
\n" ); document.write( "(x-1)^2 + y^2=16
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\n" ); document.write( "Substitute for \"y\" to get:
\n" ); document.write( "(x-1)^2 + (x+2)^2 = 16
\n" ); document.write( "x^2-2x+1 + x^2+4x+4 = 16
\n" ); document.write( "2x^2 +2x + 5 = 16
\n" ); document.write( "2x^2 + 2x - 9 = 0
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\n" ); document.write( "x = [-2 +- sqrt(4 - 4*2*-9)]/4
\n" ); document.write( "x = [-2 +- sqrt(4 + 72)]/4
\n" ); document.write( "x = [-2 +- 2sqrt(19)]/4
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\n" ); document.write( "x = (-1/2) + (1/2)sqrt(19) or x = (-1/2)-(1/2)sqrt(19)
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\n" ); document.write( "Substitute each of these into y = x+2 to get the y-values corresponding to the
\n" ); document.write( "x values:
\n" ); document.write( "Those y values will be (3/2)+(1/2)sqrt(19) and (3/2)-(1/2)sqrt(19)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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