document.write( "Question 203602: Having trouble figuring out how to due this can someone help please...\r
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document.write( "Use integration by substitution to find..\r
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document.write( "int(3x^2-2)(x^3-2x)^7 dx\r
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document.write( "have no clue thanks
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Algebra.Com's Answer #153624 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Having trouble figuring out how to due this can someone help please... \n" ); document.write( "Use integration by substitution to find.. \n" ); document.write( "int(3x^2-2)(x^3-2x)^7 dx \n" ); document.write( "---------------------------- \n" ); document.write( "Let u = x^3-2x \n" ); document.write( "Then du = 3x^2-2 dx \n" ); document.write( "------------------------ \n" ); document.write( "Substitute into your original integral and you get: \n" ); document.write( "int[u^7 du] \n" ); document.write( "--- \n" ); document.write( "Integrate wrt u to get: \n" ); document.write( "(1/8)u^8 + C \n" ); document.write( "-------------------- \n" ); document.write( "Substitute back into \"x\" to get: \n" ); document.write( "= (1/8)(x^3-2x)^8 + C \n" ); document.write( "================================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |