document.write( "Question 203602: Having trouble figuring out how to due this can someone help please...\r
\n" ); document.write( "\n" ); document.write( "Use integration by substitution to find..\r
\n" ); document.write( "\n" ); document.write( "int(3x^2-2)(x^3-2x)^7 dx\r
\n" ); document.write( "\n" ); document.write( "have no clue thanks
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Algebra.Com's Answer #153624 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Having trouble figuring out how to due this can someone help please...
\n" ); document.write( "Use integration by substitution to find..
\n" ); document.write( "int(3x^2-2)(x^3-2x)^7 dx
\n" ); document.write( "----------------------------
\n" ); document.write( "Let u = x^3-2x
\n" ); document.write( "Then du = 3x^2-2 dx
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\n" ); document.write( "Substitute into your original integral and you get:
\n" ); document.write( "int[u^7 du]
\n" ); document.write( "---
\n" ); document.write( "Integrate wrt u to get:
\n" ); document.write( "(1/8)u^8 + C
\n" ); document.write( "--------------------
\n" ); document.write( "Substitute back into \"x\" to get:
\n" ); document.write( "= (1/8)(x^3-2x)^8 + C
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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