document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=203550>Question 203550</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you help me with this word problem?\r<BR>\n" );
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document.write( "Dave has a collection of nickles and dimes that is worth $6.05.  If the number of dimes was doubled and the number of nickels was decreases by 10, the value of the coins would be $9.85.  How many dimes and nickles does he have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #153603 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=153603\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> n(.05) + d(.10) = 6.05 ___ 5n + 10d = 605 ___ 5n = 605 - 10d\r<BR>\n" );
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document.write( "(n - 10)(.05) + 2d(.10) = 9.85 ___ 5n - 50 + 20d = 985\r<BR>\n" );
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document.write( "substituting ___ 605 - 10d - 50 + 20d = 985 ___ 10d = 430 ___ d = 43\r<BR>\n" );
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document.write( "substituting ___ 5n = 605 - 430 ___ 5n = 175 ___ n = 35 </SPAN>\n" );
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