document.write( "Question 203510: Could someone help me with this one? I have trouble with word problems? You are greatly appreciated.\r
\n" ); document.write( "\n" ); document.write( "An express train and a local train both leave Gray’s Lake at 12:00 noon and head for Chicago 60 miles away. The express travels twice as fast as the local and arrives 2 hours ahead of it. Find the speed of each train. \r
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Algebra.Com's Answer #153583 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
An express train and a local train both leave Gray’s Lake at 12:00 noon and head
\n" ); document.write( " for Chicago 60 miles away. The express travels twice as fast as the local and
\n" ); document.write( " arrives 2 hours ahead of it. Find the speed of each train.
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\n" ); document.write( "Let s = speed of the freight
\n" ); document.write( "then
\n" ); document.write( "2s = speed of the express
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\n" ); document.write( "Write a time equation: Time = \"dist%2Fspeed\"
\n" ); document.write( "Freight time = Express time + 2 hrs
\n" ); document.write( "\"60%2Fs\" = \"60%2F%282s%29\" + 2
\n" ); document.write( "Multiply equation by 2s, results:
\n" ); document.write( "2(60) = 60 + 2(2s)
\n" ); document.write( "120 = 60 + 4s
\n" ); document.write( "120 - 60 = 4s
\n" ); document.write( "60 = 4s
\n" ); document.write( "s = \"60%2F4\"
\n" ); document.write( "s = 15 mph is the freight,
\n" ); document.write( "then
\n" ); document.write( "2(15) = 30 mph is express
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\n" ); document.write( "Check solution by finding the time of each train
\n" ); document.write( "60/15 = 4 hr
\n" ); document.write( "60/30 = 2 hr
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\n" ); document.write( "differ = 2 hrs
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