document.write( "Question 203512: a cyclist traveled at at rate of 32 mph to visit a nearby town. The cyclist averaged 10 mph on the return trip. If the trip took 6.3 hours, find the distance to the nearby town. \n" ); document.write( "
Algebra.Com's Answer #153565 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=RT OR T=D/R \n" ); document.write( "X/32+X/10=6.3 \n" ); document.write( "(10X+32X)/(10*32)=6.3 \n" ); document.write( "42X/320=6.3 \n" ); document.write( "42X=6.3*320 \n" ); document.write( "42X=2,016 \n" ); document.write( "X=2,016/42 \n" ); document.write( "X=48 MILES IS THE DISTANCE TO THE NEARBY TOWN. \n" ); document.write( "PROOF: \n" ); document.write( "48/32+48/10=6.3 \n" ); document.write( "1.5+4.8=6.3 \n" ); document.write( "6.3=6.3 \n" ); document.write( " \n" ); document.write( " |