document.write( "Question 203514: Factor this problem
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document.write( "x^3 y+2x^2 y^2+xy^3 \n" );
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Algebra.Com's Answer #153548 by jsmallt9(3758)![]() ![]() ![]() You can put this solution on YOUR website! When factoring, always start by factoring out the Greatest Common Factor (GCF) (unless the GCF is a 1). Then try factoring using any other techniques you may know:
\n" ); document.write( "And you keep factoring, using and reusing any of the above until you cannot factor any further. \n" ); document.write( "Now let's try to use this on your expression. \n" ); document.write( " \n" ); document.write( "Start with the GCF. We are looking for the greatest/longest set of factors whic are factors of every term. The terms are: \n" ); document.write( " \r\n" ); document.write( "x^3*y = x*x*x*y\r\n" ); document.write( "2x^2*y^2 = 2*x*x* y*y\r\n" ); document.write( "x*y^3 = x* y*y*y\r\n" ); document.write( " \n" ); document.write( "Looking at the above it should be clear that the only factors that are in all three terms are an x and a y. So the GCF is the their product: x*y. When you factor out the GCF you write the GCF and then, in parentheses, you write each term of the polynomial with the GCF removed: \n" ); document.write( " \n" ); document.write( "Now we try other factoring techniques. This is pretty easy at this point because it should be pretty clear how (x^2 + 2xy + y^2) matches the first perfect square trinomial pattern. So we can factor it using the pattern: \n" ); document.write( " \n" ); document.write( "This will not factor any further so we are done. \n" ); document.write( " |