document.write( "Question 203504: The consumer price index compares the cost of goods and services over various years. The same goods and services that cost $100 in 1967 cost $148.50 in 1977. Assuming exponential growth, find the value of these same goods and services in 1999.\r
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document.write( "After what period of time did the same goods and services cost double that of 1967?
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document.write( "Hint: x.xx years \r
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document.write( "can someone help please
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Algebra.Com's Answer #153535 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The consumer price index compares the cost of goods and services over various years. The same goods and services that cost $100 in 1967 cost $148.50 in 1977. Assuming exponential growth, find the value of these same goods and services in 1999. \n" ); document.write( "--- \n" ); document.write( "Let x=0 correspond to the year 1967. \n" ); document.write( "------------------------------------ \n" ); document.write( "Form::::::::: y = a*b^x \n" ); document.write( "(0,100):::: 100 = a*b^0 \n" ); document.write( "(10,148.50):148.5= a*b^10 \n" ); document.write( "--- \n" ); document.write( "1st equation says a = 100 \n" ); document.write( "Then b = 1.485^(1/10) \n" ); document.write( "-- \n" ); document.write( "So the equation is y = 100 \n" ); document.write( "------------------------------------------ \n" ); document.write( "find the value of these same goods and services in 1999. \n" ); document.write( "x = 1999-1967 = 32 \n" ); document.write( "y = 100*(1.485^(3.2) = $354.43 \n" ); document.write( "---------------------------------------- \n" ); document.write( "After what period of time did the same goods and services cost double that of 1967? \n" ); document.write( "200 = 100(1.485^(x/10)) \n" ); document.write( "--- \n" ); document.write( "1.485^(x/10) = 2 \n" ); document.write( "(x/10)log(1.485) = log(2) \n" ); document.write( "(x/10) = 1.753 \n" ); document.write( "x = 17.53 years \n" ); document.write( "--- \n" ); document.write( "Year: 1967 + 17.53 = 1969 when rounded up. \n" ); document.write( "=============================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |