document.write( "Question 203504: The consumer price index compares the cost of goods and services over various years. The same goods and services that cost $100 in 1967 cost $148.50 in 1977. Assuming exponential growth, find the value of these same goods and services in 1999.\r
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\n" ); document.write( "\n" ); document.write( "After what period of time did the same goods and services cost double that of 1967?
\n" ); document.write( "Hint: x.xx years \r
\n" ); document.write( "\n" ); document.write( "can someone help please
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Algebra.Com's Answer #153535 by stanbon(75887)\"\" \"About 
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The consumer price index compares the cost of goods and services over various years. The same goods and services that cost $100 in 1967 cost $148.50 in 1977. Assuming exponential growth, find the value of these same goods and services in 1999.
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\n" ); document.write( "Let x=0 correspond to the year 1967.
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\n" ); document.write( "Form::::::::: y = a*b^x
\n" ); document.write( "(0,100):::: 100 = a*b^0
\n" ); document.write( "(10,148.50):148.5= a*b^10
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\n" ); document.write( "1st equation says a = 100
\n" ); document.write( "Then b = 1.485^(1/10)
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\n" ); document.write( "So the equation is y = 100
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\n" ); document.write( "find the value of these same goods and services in 1999.
\n" ); document.write( "x = 1999-1967 = 32
\n" ); document.write( "y = 100*(1.485^(3.2) = $354.43
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\n" ); document.write( "After what period of time did the same goods and services cost double that of 1967?
\n" ); document.write( "200 = 100(1.485^(x/10))
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\n" ); document.write( "1.485^(x/10) = 2
\n" ); document.write( "(x/10)log(1.485) = log(2)
\n" ); document.write( "(x/10) = 1.753
\n" ); document.write( "x = 17.53 years
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\n" ); document.write( "Year: 1967 + 17.53 = 1969 when rounded up.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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