document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=203481>Question 203481</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I actually attempted the examples in my book but still do not grasp the concept if I can actually get someone to get to break this down for me i might be able to do the rest on my own:\r<BR>\n" );
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document.write( "y= -3x+19<BR>\n" );
document.write( "y= 2x-1\r<BR>\n" );
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document.write( "and \r<BR>\n" );
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document.write( "x+3y=2<BR>\n" );
document.write( "-x+y=1 thank you \r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #153509 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=153509\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The first one lends itself to the substitution method<BR>\n" );
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document.write( "y= -3x+19<BR>\n" );
document.write( "y= 2x - 1<BR>\n" );
document.write( "Look at the 2nd equation, it should be apparent that we can<BR>\n" );
document.write( "substitute (2x-1) for y in the 1st equation, then find x<BR>\n" );
document.write( "2x - 1 = -3x + 19<BR>\n" );
document.write( "2x + 3x = 19 + 1<BR>\n" );
document.write( "5x = 20<BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=20%2F5 ALIGN=MIDDLE  ALT=\"20%2F5\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = 4<BR>\n" );
document.write( "Use the 2nd equation to find y. Substitute 4 for x<BR>\n" );
document.write( "y = 2(4) - 1<BR>\n" );
document.write( "y = 8 - 1<BR>\n" );
document.write( "y = 7<BR>\n" );
document.write( "Check your solutions by substitution in the 1st equation<BR>\n" );
document.write( "y = - 3x + 19<BR>\n" );
document.write( "7 = -3(4) + 19<BR>\n" );
document.write( "7 = -12 + 19; confirms our solutions<BR>\n" );
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document.write( "The 2nd equation lends itself to the elimination method<BR>\n" );
document.write( " x + 3y = 2<BR>\n" );
document.write( "-x +  y = 1<BR>\n" );
document.write( "-------------adding these eliminates x, find y<BR>\n" );
document.write( "0x + 4y = 3<BR>\n" );
document.write( "y = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2F4 ALIGN=MIDDLE  ALT=\"3%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Find x using the 1st equation, substitute 3/4 of y<BR>\n" );
document.write( "x + 3(3/4) = 2<BR>\n" );
document.write( "x + 9/4 = 2<BR>\n" );
document.write( "x = 2 - 9/4<BR>\n" );
document.write( "x = -1/4<BR>\n" );
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document.write( "Check solution in the 2nd equation<BR>\n" );
document.write( "-x + y = 1<BR>\n" );
document.write( "-(-1/4) + (3/4) = 1<BR>\n" );
document.write( "+1/4 + 3/4 = 1 </SPAN>\n" );
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