document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=3452>Question 3452</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the equation of this graph.the points are (6,6)and (2,4) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #1535 by </B><A HREF=/tutors/aboutme.mpl?userid=drglass><B>drglass(89)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drglass><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=1535\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To find the equation of a line that includes the points (6,6) and (2,4), use the equation for a line, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+mx+%2B+b ALIGN=MIDDLE  ALT=\"y+=+mx+%2B+b\"   DISABLED_style= \"max-width:90%; height:auto;\" >, where m is the slope of the line and b is the intercept. For the sake of discussion, let's call (6,6) P1 and we'll call (2,4) P2<br><BR>\n" );
document.write( "First, find the slope. The slope is the \"rise over the run\" or the change in y divided by the change in x. We have two points on the line, so we know that the line \"rises\" from 4 to 6 (the y values of points P2 and P3). The point also \"runs\" from 2 to 6 (the x values of points P2 and P1). The distance of the rise is 6 - 4 or 2 and the distance of the run is 6 - 2 or 4. Therefore the slope is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m+=+2%2F4+=+1%2F2 ALIGN=MIDDLE  ALT=\"m+=+2%2F4+=+1%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<br><BR>\n" );
document.write( "With the slope, we have the equation  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+%281%2F2%29x+%2B+b ALIGN=MIDDLE  ALT=\"y+=+%281%2F2%29x+%2B+b\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Let's see what happens to the equation when we supply it with the x and y values on one point on the line, say P1. Our equation becomes <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6+=+%281%2F2%296+%2B+b+=+3+%2B+b ALIGN=MIDDLE  ALT=\"6+=+%281%2F2%296+%2B+b+=+3+%2B+b\"   DISABLED_style= \"max-width:90%; height:auto;\" >. To find b, subtract 3 from both sides to get b = 3.<br><BR>\n" );
document.write( "The equation of the line is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+%281%2F2%29+x+%2B+3 ALIGN=MIDDLE  ALT=\"y+=+%281%2F2%29+x+%2B+3\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
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document.write( "To verify this, put the x and y values of points P1 and P2 into the equation. If these points are on the line, the equation will hold.<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+6+=+%281%2F2%296+%2B+3+=+3+%2B+3+=+6+ ALIGN=MIDDLE  ALT=\"+6+=+%281%2F2%296+%2B+3+=+3+%2B+3+=+6+\"   DISABLED_style= \"max-width:90%; height:auto;\" > P1 holds<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+4+=+%281%2F2%292+%2B+3+=+1+%2B+3+=+4+ ALIGN=MIDDLE  ALT=\"+4+=+%281%2F2%292+%2B+3+=+1+%2B+3+=+4+\"   DISABLED_style= \"max-width:90%; height:auto;\" > P2 holds<br> </SPAN>\n" );
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