document.write( "Question 203449: Jerome's experiment requires him to mix a 50%-acid solution with an 80%-acid solution to create 200 mL of a 68%-acid solution. How much 50%-acid solution and how much 80%-acid solution should he use? \n" ); document.write( "
Algebra.Com's Answer #153496 by rfer(16322)\"\" \"About 
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let x=.50 base=80ml
\n" ); document.write( "let 200-x=.80 base=120ml
\n" ); document.write( ".5x+.8(200-x)=.68*200
\n" ); document.write( ".5x+160-.8x=136
\n" ); document.write( "-.3x=-24
\n" ); document.write( "x=80
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