document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=203392>Question 203392</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0741913658/algebrahomeworkh>academic systems intermediate algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Solve for x: 24/8x - x/3 = 3-x/6.\r<BR>\n" );
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document.write( "I have tried multiplying by the lcd, I have mulitplied by 8x to try and clear the fractions, but I think I am missing a step somewhere and I cannot figure it out. I looked in the back of the book and found the answers are x=3 or x=-6, but I cannot see how that is possible. Thank you in advance for your help.\r<BR>\n" );
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document.write( "Jody </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #153474 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=153474\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the LCD for 8x, 3, and 6 is 24x\r<BR>\n" );
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document.write( "24/8x - x/3 = (3-x) / 6\r<BR>\n" );
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document.write( "72 - 8x^2 = 12x - 4x^2 ___ 0 = 4x^2 + 12x - 72 ___ 0 = x^2 + 3x - 18\r<BR>\n" );
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document.write( "factoring ___ 0 = (x + 6)(x - 3) </SPAN>\n" );
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