document.write( "Question 203385: Ok, so here is the word problem, can you tell me if I set it up correctly?!
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document.write( "Jack bought a new camera but when it came time to record the purchase in his check register all he could remember was that the price was:
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document.write( " six (6) less than the square of this amount is equal to the amount itself.\r
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document.write( "So the equation should look like x^2-6=x\r
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document.write( "Am I correct? \n" );
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Algebra.Com's Answer #153452 by Theo(13342)![]() ![]() You can put this solution on YOUR website! you are correct. \n" ); document.write( "x = x^-6 \n" ); document.write( "solving that, we get x = 3 as follows: \n" ); document.write( "x = x^2 - 6 \n" ); document.write( "subtract x from both sides to get: \n" ); document.write( "x^2 - x - 6 = 0 \n" ); document.write( "which becomes: \n" ); document.write( "(x-3)*(x+2) = 0 \n" ); document.write( "which means that: \n" ); document.write( "x = 3 or x = -2 \n" ); document.write( "since x can't be negative, then x = 3 is your only possible solution. \n" ); document.write( "----- \n" ); document.write( "3 = 9-6 = 3 is good, so x = 3 is your answer and your equation of: \n" ); document.write( "x^ - 6 = x \n" ); document.write( "is good. \n" ); document.write( "----- \n" ); document.write( " |