document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=203366>Question 203366</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help with this algebra problem..\r<BR>\n" );
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document.write( "Solve by substitution \r<BR>\n" );
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document.write( "3x + 6y = 18\r<BR>\n" );
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document.write( "-6x + y = 16\r<BR>\n" );
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document.write( "Thank you for any help!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #153430 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=153430\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve by substitution <BR>\n" );
document.write( "3x + 6y = 18 <BR>\n" );
document.write( "-6x + y = 16 <BR>\n" );
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document.write( "Solve the 2nd equation for \"y\":<BR>\n" );
document.write( "y = 6x+16<BR>\n" );
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document.write( "Substitute into the 1st equation:<BR>\n" );
document.write( "3x + 6(6x+16) = 18<BR>\n" );
document.write( "3x + 36x + 96 = 18<BR>\n" );
document.write( "39x = -78<BR>\n" );
document.write( "x = -2<BR>\n" );
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document.write( "Since y = 6x+16, y = 6*-2+16 = 4<BR>\n" );
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document.write( "Ans: (-2,4)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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