document.write( "Question 203282: A rocket is launched from atop a 92 foot cliff with an initial vertical velocity of 112 feet per second. The height of the rocket t seconds after launch is given by the equation h= -16t^2+112t+92. Graph the equation to find out how long after the rocket is launched it will hit the ground. Estimate your answer to the nearest tenth of a second. \n" ); document.write( "
Algebra.Com's Answer #153383 by Earlsdon(6294)\"\" \"About 
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Graph:
\n" ); document.write( "\"h%28t%29+=+-16t%5E2%2B112t%2B92\"
\n" ); document.write( "\"graph%28400%2C400%2C-5%2C10%2C-5%2C290%2C-16x%5E2%2B112x%2B92%29\"
\n" ); document.write( "When h (vertical axis) = 0, t = 7.75 approximately.
\n" ); document.write( "So the rocket will hit the ground (h = 0) in about 7.75 seconds after launch.
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