document.write( "Question 203302: A plane travels at a speed of 220mph in still air. Flying with a tailwind, the plane is clocked over a distance of 975 miles. Flying against a headwind it takes 1 hour more time to complete the return trip. What was the wind velocity. Round to nearest tenth. \n" ); document.write( "
Algebra.Com's Answer #153372 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A plane travels at a speed of 220mph in still air. Flying with a tailwind, the plane is clocked over a distance of 975 miles. Flying against a headwind it takes 1 hour more time to complete the return trip. What was the wind velocity. Round to nearest tenth. \n" ); document.write( "----------------------------------------- \n" ); document.write( "With-the-wind DATA: \n" ); document.write( "distance = 975 miles ; rate = (220+w) mph ; time = d/r = 975/(220+w) hrs \n" ); document.write( "------------------------------------------------- \n" ); document.write( "Against-the-wind DATA: \n" ); document.write( "distance = 975 miles ; rate = (220-w) mph ; time = d/r = 975/(220-w) hrs \n" ); document.write( "-------------------------------------------------- \n" ); document.write( "Equation: \n" ); document.write( "time against - time with = 1 hr \n" ); document.write( "975/(220-w) - 975/(220+w) = 1 \n" ); document.write( "--- \n" ); document.write( "975(220+w) - 975(220-w) = (220+w)(220-w) \n" ); document.write( "2(975w) = 220^2 - w^2 \n" ); document.write( "w^2 + 1950w - 46450 = 0 \n" ); document.write( "Positive solution: \n" ); document.write( "w = 24.512 mph (rate of the wind) \n" ); document.write( "=========================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=========================================== \n" ); document.write( " \n" ); document.write( " |