document.write( "Question 28142: Please help us write out this equation. I couldn't find anything like this problem in your previous answers. This problem is word for word from my son's algebra book.\r
\n" );
document.write( "\n" );
document.write( "The sum of the digits of a two-digit number is 9. If the digits are reversed, the new number is 27 less than the original. Find the original number.\r
\n" );
document.write( "\n" );
document.write( "Thanks a billion in advance for your help. \n" );
document.write( "
Algebra.Com's Answer #15337 by sdmmadam@yahoo.com(530)![]() ![]() ![]() You can put this solution on YOUR website! The sum of the digits of a two-digit number is 9. If the digits are reversed, the new number is 27 less than the original. Find the original number.\r \n" ); document.write( "\n" ); document.write( "Let the digit in the units place be u and \n" ); document.write( "let the digit in the tens place be t \n" ); document.write( "Then the two digit number is givn by (10t+u)----(*) \n" ); document.write( "By data the sum of the digits of the two digit number is 9 \n" ); document.write( "That is (u+t) = 9----(1) \n" ); document.write( "Now if the digits are reversed, that is u and t switch places then now t is the unit place digit and u is the tenth place digit \n" ); document.write( "This reversed number is (10u+t)and it is given to be 27 \n" ); document.write( "That is (10u+t) = 27 ----(2) \n" ); document.write( "Putting (1) in (2) (using t = 9-u ) \n" ); document.write( " 10u +(9-u) = 27 \n" ); document.write( " (10u-u)= 27-9 \n" ); document.write( " 9u = 18 \n" ); document.write( " u = 18/9 = 2 \n" ); document.write( "u= 2 in (1): u+t = 9 implies t = 7 \n" ); document.write( "Therefore the original number is got by putting t=7 and u =2 in (*) \n" ); document.write( "(10t+u) = 10X7 + 2 = 70+2 = 72 \n" ); document.write( "Answer: The required number is 72 \n" ); document.write( "Verification: IF we add up the digits in 72 we get 9 and 72 when reversed is 27. \n" ); document.write( "Therefore our answer72 is correct \n" ); document.write( " |