document.write( "Question 203284: The height, h (in feet), of a falling object on Mars is given by h=-6t^2+s , where t is the time in seconds and s is the initial height in feet. If an object were dropped from a height of 237 feet, how long would it take to travel half the distance to the ground? (Round to two decimal places.) \n" ); document.write( "
Algebra.Com's Answer #153359 by ankor@dixie-net.com(22740)\"\" \"About 
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The height, h (in feet), of a falling object on Mars is given by h=-6t^2+s ,
\n" ); document.write( " where t is the time in seconds and s is the initial height in feet.
\n" ); document.write( " If an object were dropped from a height of 237 feet, how long would it take to
\n" ); document.write( " travel half the distance to the ground? (Round to two decimal places.)
\n" ); document.write( ":
\n" ); document.write( "half the distance: 237/2 = 118.5 ft
\n" ); document.write( ":
\n" ); document.write( "-6t^2 + 237 = 118.5
\n" ); document.write( "-6t^2 = 118.5 - 237
\n" ); document.write( "-6t^2 = -118.5
\n" ); document.write( "6t^2 = 118.5; multiplied by -1
\n" ); document.write( "t^2 = \"118.5%2F6\"
\n" ); document.write( "t^2 = 19.75
\n" ); document.write( "t = \"sqrt%2819.75%29\"
\n" ); document.write( "t = 4.44 sec to reach half way down
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solution using 4.44 sec
\n" ); document.write( "h = -6(4.44^2) + 237
\n" ); document.write( "h = -6(19.75) + 237
\n" ); document.write( "h = -118.5 + 237
\n" ); document.write( "h 118.5 \n" ); document.write( "
\n" );