document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=203267>Question 203267</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0130452696/algebrahomeworkh>Mathematics For Technical trades</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> If a cylinder has  a radius of 3 centimeters and a height of 10 centimeters, calculate its:<BR>\n" );
document.write( "a. lateral surface area<BR>\n" );
document.write( "b. total surface area <BR>\n" );
document.write( "c. Volume </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #153352 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=153352\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> FInd the lateral surface area, the total surface area, and the volume of a cylinder whose radius (r) is 3 cm. and whose height (h) is 10 cm.<BR>\n" );
document.write( "a) Lateral surface area is:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%5Bl%5D+=+2%28pi%29r%2Ah ALIGN=MIDDLE  ALT=\"A%5Bl%5D+=+2%28pi%29r%2Ah\"   DISABLED_style= \"max-width:90%; height:auto;\" > (Area = Circumference times the height) Substitute r = 3 and h = 10.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%5Bl%5D+=+2%28pi%29%283%29%2810%29 ALIGN=MIDDLE  ALT=\"A%5Bl%5D+=+2%28pi%29%283%29%2810%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28A%5Bl%5D+=+60%28pi%29%29 ALIGN=MIDDLE  ALT=\"highlight%28A%5Bl%5D+=+60%28pi%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > This is the exact answer.  For an approximation, substitute <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi+=+3.14 ALIGN=MIDDLE  ALT=\"pi+=+3.14\"   DISABLED_style= \"max-width:90%; height:auto;\" > to get:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%5Bl%5D+=+60%283.14%29 ALIGN=MIDDLE  ALT=\"A%5Bl%5D+=+60%283.14%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%28A%5Bl%5D+=+188.4%29 ALIGN=MIDDLE  ALT=\"highlight_green%28A%5Bl%5D+=+188.4%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >sq.cm.<BR>\n" );
document.write( "--------------------------------------------<BR>\n" );
document.write( "b) The total surface area of the cylinder is the sum of the lateral surface area (see a) above) and the areas of the top & bottom of the cylinder.<BR>\n" );
document.write( "These areas (top & bottom) are the same so you need compute only one and then double it to get both.<BR>\n" );
document.write( "Area of the top:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%5Bt%5D+=+%28pi%29r%5E2 ALIGN=MIDDLE  ALT=\"A%5Bt%5D+=+%28pi%29r%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Substitute r = 3.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%5Bt%5D+=+%28pi%29%283%29%5E2 ALIGN=MIDDLE  ALT=\"A%5Bt%5D+=+%28pi%29%283%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%5Bt%5D+=+9%28pi%29 ALIGN=MIDDLE  ALT=\"A%5Bt%5D+=+9%28pi%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > now double this to include the bottom:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%5Bb%5D+=+2%289%29%28pi%29 ALIGN=MIDDLE  ALT=\"A%5Bb%5D+=+2%289%29%28pi%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28A%5Bb%5D+=+18%28pi%29%29 ALIGN=MIDDLE  ALT=\"highlight%28A%5Bb%5D+=+18%28pi%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > For an approximation, substitute <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi+=+3.14 ALIGN=MIDDLE  ALT=\"pi+=+3.14\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%5Bb%5D+=+%2818%29%283.14%29 ALIGN=MIDDLE  ALT=\"A%5Bb%5D+=+%2818%29%283.14%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%28A%5Bb%5D+=+56.52%29 ALIGN=MIDDLE  ALT=\"highlight_green%28A%5Bb%5D+=+56.52%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >sq.cm.<BR>\n" );
document.write( "Now add this to the lateral surface area (<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=60%28pi%29 ALIGN=MIDDLE  ALT=\"60%28pi%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >) to get:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%5BT%5D+=+60%28pi%29%2B18%28pi%29 ALIGN=MIDDLE  ALT=\"A%5BT%5D+=+60%28pi%29%2B18%28pi%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28A%5BT%5D+=+78%28pi%29%29 ALIGN=MIDDLE  ALT=\"highlight%28A%5BT%5D+=+78%28pi%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Exact answer, or approximately:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%28A%5BT%5D+=+244.92%29 ALIGN=MIDDLE  ALT=\"highlight_green%28A%5BT%5D+=+244.92%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >sq.cm.<BR>\n" );
document.write( "-----------------------------------------------<BR>\n" );
document.write( "c) The volume of a cylinder is given by:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=V+=+%28pi%29%2Ar%5E2%2Ah ALIGN=MIDDLE  ALT=\"V+=+%28pi%29%2Ar%5E2%2Ah\"   DISABLED_style= \"max-width:90%; height:auto;\" > Substitute r = 3 and h = 10.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=V+=+%28pi%29%283%29%5E2%2810%29 ALIGN=MIDDLE  ALT=\"V+=+%28pi%29%283%29%5E2%2810%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28V+=+90%28pi%29%29 ALIGN=MIDDLE  ALT=\"highlight%28V+=+90%28pi%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > or approximately:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=V+=+90%283.14%29 ALIGN=MIDDLE  ALT=\"V+=+90%283.14%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%28V+=+282.6%29 ALIGN=MIDDLE  ALT=\"highlight_green%28V+=+282.6%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >cu.cm. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );