document.write( "Question 28098: What is the slope of the line y+4=2(x+5) \n" ); document.write( "
Algebra.Com's Answer #15333 by sdmmadam@yahoo.com(530)\"\" \"About 
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28098 (2006-02-21 18:42:58): What is the slope of the line y+4=2(x+5)\r
\n" ); document.write( "\n" ); document.write( "What is the slope of the line y+4=2(x+5)
\n" ); document.write( "You can read the equation and give the slope as 2
\n" ); document.write( "How? When the coefficient of y is 1 on one side,the coefficinet of x on the other side gives the slope
\n" ); document.write( "Note:The standard slope and y-intercept form
\n" ); document.write( "y+4=2(x+5)
\n" ); document.write( "y+4 = 2x+10
\n" ); document.write( "y =2x+(10-4) (taking 4 from the left to the right, change side then change sign)
\n" ); document.write( "y = 2x+6
\n" ); document.write( "slope = 2
\n" ); document.write( "This is the standard slope and y-intercept form of equation :
\n" ); document.write( "y = (m)x +c
\n" ); document.write( "slope = m = 2 and y-intercept = c = 6
\n" ); document.write( "Note: When the coefficient of y is 1 on one side and when the x-term and the constant term are on the other side, the coefficinet of x gives the slope and the constant part gives the y-intercept.
\n" ); document.write( "Note: slope= 2>0 (slope is positive)implies the angle of inclination of the line with the x-axis is acute and so the course of the straight line is from the first to the third quadrant and since the y-intercept is positive the line travels via the second quadrant
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