document.write( "Question 203097: Loren drove 200 miles at a certain rate, and his wife, Lois, drove 100 miles at a rate 10 mph slower. If Loren had driven for the entire trip, they would have arrived 30 minutes sooner. What was Loren's rate? \n" ); document.write( "
Algebra.Com's Answer #153278 by ankor@dixie-net.com(22740)\"\" \"About 
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Loren drove 200 miles at a certain rate, and his wife, Lois, drove 100 miles
\n" ); document.write( " at a rate 10 mph slower. If Loren had driven for the entire trip,
\n" ); document.write( " they would have arrived 30 minutes sooner. What was Loren's rate?
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\n" ); document.write( "Let r = Loren's rate
\n" ); document.write( "then
\n" ); document.write( "(r-10) = Lois' rate
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\n" ); document.write( "Write a time equation: Time = \"dist%2Frate\"
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\n" ); document.write( "Convert 30 min to .5 hrs
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\n" ); document.write( "Loren's drive time + Lois drive time = Loren's drive time + 30 min (.5 hr)
\n" ); document.write( "\"200%2Fr\" + \"100%2F%28%28r-10%29%29\" = \"300%2Fr\" + .5
\n" ); document.write( "multiply equation by: r(r-10), results
\n" ); document.write( "200(r-10) + 100r = 300(r-10) + .5r(r-10)
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\n" ); document.write( "200r - 2000 + 100r = 300r - 3000 + .5r^2 - 5r
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\n" ); document.write( "300r - 2000 = 300r - 3000 + .5r^2 - 5r
\n" ); document.write( ":
\n" ); document.write( "0 = 300r - 300r - 3000 + 2000 .5r^2 - 5r
\n" ); document.write( "A quadratic equation
\n" ); document.write( ".5r^2 - 5r - 1000 = 0
\n" ); document.write( "Multiply by 2 to get rid of the decimal
\n" ); document.write( "r^2 - 10r - 2000 = 0
\n" ); document.write( "Factor
\n" ); document.write( "(r-50)(r+40) = 0
\n" ); document.write( "Positive solution
\n" ); document.write( "r = 50 mph is Loren's speed
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\n" ); document.write( "Check solution in original equation (40 mph is Lois' speed)
\n" ); document.write( "\"200%2F50\" + \"100%2F40\" = \"300%2F50\" + .5
\n" ); document.write( "4 + 2.5 = 6 + .5
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