document.write( "Question 203097: Loren drove 200 miles at a certain rate, and his wife, Lois, drove 100 miles at a rate 10 mph slower. If Loren had driven for the entire trip, they would have arrived 30 minutes sooner. What was Loren's rate? \n" ); document.write( "
Algebra.Com's Answer #153278 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Loren drove 200 miles at a certain rate, and his wife, Lois, drove 100 miles \n" ); document.write( " at a rate 10 mph slower. If Loren had driven for the entire trip, \n" ); document.write( " they would have arrived 30 minutes sooner. What was Loren's rate? \n" ); document.write( ": \n" ); document.write( "Let r = Loren's rate \n" ); document.write( "then \n" ); document.write( "(r-10) = Lois' rate \n" ); document.write( ": \n" ); document.write( "Write a time equation: Time = \n" ); document.write( ": \n" ); document.write( "Convert 30 min to .5 hrs \n" ); document.write( ": \n" ); document.write( "Loren's drive time + Lois drive time = Loren's drive time + 30 min (.5 hr) \n" ); document.write( " \n" ); document.write( "multiply equation by: r(r-10), results \n" ); document.write( "200(r-10) + 100r = 300(r-10) + .5r(r-10) \n" ); document.write( ": \n" ); document.write( "200r - 2000 + 100r = 300r - 3000 + .5r^2 - 5r \n" ); document.write( ": \n" ); document.write( "300r - 2000 = 300r - 3000 + .5r^2 - 5r \n" ); document.write( ": \n" ); document.write( "0 = 300r - 300r - 3000 + 2000 .5r^2 - 5r \n" ); document.write( "A quadratic equation \n" ); document.write( ".5r^2 - 5r - 1000 = 0 \n" ); document.write( "Multiply by 2 to get rid of the decimal \n" ); document.write( "r^2 - 10r - 2000 = 0 \n" ); document.write( "Factor \n" ); document.write( "(r-50)(r+40) = 0 \n" ); document.write( "Positive solution \n" ); document.write( "r = 50 mph is Loren's speed \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution in original equation (40 mph is Lois' speed) \n" ); document.write( " \n" ); document.write( "4 + 2.5 = 6 + .5 \n" ); document.write( " \n" ); document.write( " |