document.write( "Question 203068: Please help me solve this word problem.
\n" ); document.write( "Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 60 mils per hour and train B is traveling at 70 mils per hour. Train A passes a station at 5:15 A. M. if train B passes station at 5:27 A.M, what time train b catch up train A?
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Algebra.Com's Answer #153234 by ankor@dixie-net.com(22740)\"\" \"About 
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Trains A and B are traveling in the same direction on parallel tracks.
\n" ); document.write( " Train A is traveling at 60 mils per hour and train B is traveling at 70 mils per hour.
\n" ); document.write( "Train A passes a station at 5:15 A. M. if train B passes station at 5:27 A.M,
\n" ); document.write( " what time train b catch up train A?
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\n" ); document.write( "from the given information, we know that train B is 12 min (.2 hr) behind
\n" ); document.write( " train A, when train A passes the station
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\n" ); document.write( "The distance between the trains at this time: .2 * 70 = 14 mi
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\n" ); document.write( "Let t = time required for train B to catch train a
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\n" ); document.write( "write a distance equation: Dist = speed * time
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\n" ); document.write( "Train A travel dist = Train b travel dist + 14 mi
\n" ); document.write( "70t = 60t + 14
\n" ); document.write( "70t - 60t = 14
\n" ); document.write( "10t = 14
\n" ); document.write( "t = \"14%2F10\"
\n" ); document.write( "t = 1.4 hr or 1 hr 24 min
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\n" ); document.write( "5:15 + 1:24 = 6:39 AM, B catches A
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\n" ); document.write( "Check solution by finding the dist traveled by each train
\n" ); document.write( "70*1.4 = 98 mi
\n" ); document.write( "60*1.4 = 84 mi
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\n" ); document.write( "differ = 14 mi
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