document.write( "Question 203094: Can you please help me write out and solve the equation for this word problem?\r
\n" ); document.write( "\n" ); document.write( "A car leaves a town traveling at 60 miles per hour. How long will it take a second car traveling at 75 miles per hour to catch up to the first car if it leaves 2 hours later?\r
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Algebra.Com's Answer #153227 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let's make t = time (in hours) that the first car travels.\r
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\n" ); document.write( "\n" ); document.write( "First, let's set up the equation for the first car to leave. Recall that the distance \"d\" equals the speed \"r\" multiplied by the time \"t\". So this means that \r
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\n" ); document.write( "\n" ); document.write( "\"d=rt\"\r
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\n" ); document.write( "\n" ); document.write( "\"d=60t\" Plug in \"r=60\" (the speed of the first car)\r
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\n" ); document.write( "\n" ); document.write( "Now let's set up the second equation (for the second car). Since the first car travels \"t\" hours, and it has a 2 hour head start, this means that the second car is going to travel \"t-2\" hours (eg, the first car travels t=6 hours and the second travels t-2=6-2=4 hours). \r
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\n" ); document.write( "\n" ); document.write( "So this means that we start with \"d=rt\" and plug in \"r=75\" and replace \"t\" with \"t-2\" to get \"d=75%28t-2%29\"\r
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\n" ); document.write( "\n" ); document.write( "Note: the \"d\"s of both equations are the same \"d\" since the cars will have gone the distance when they meet.\r
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\n" ); document.write( "\n" ); document.write( "So we have the two equations \"d=60t\" and \"d=75%28t-2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"d=60t\" Start with the first equation.\r
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\n" ); document.write( "\n" ); document.write( "\"75%28t-2%29=60t\" Plug in \"d=75%28t-2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"75t-150=60t\" Distribute.\r
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\n" ); document.write( "\n" ); document.write( "\"75t=60t%2B150\" Add \"150\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"75t-60t=150\" Subtract \"60t\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"15t=150\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"t=%28150%29%2F%2815%29\" Divide both sides by \"15\" to isolate \"t\".\r
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\n" ); document.write( "\n" ); document.write( "\"t=10\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"t=10\" which means that the first car traveled for 10 hours\r
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\n" ); document.write( "\n" ); document.write( "Subtract 2 from this answer to get \"10-2=8\". So this tells us that the second car traveled 8 hours.\r
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\n" ); document.write( "\n" ); document.write( "So it takes 8 hours for the second car to catch up and meet the first car.
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