document.write( "Question 203063: (15ab/4)(8/9a^2b^2)= ?\r
\n" ); document.write( "\n" ); document.write( "(6a/8b)/(10c/12d)= ?\r
\n" ); document.write( "\n" ); document.write( "(2x^2+x-3/9)[(x+1)^2/2x^2+5x+3)= ?\r
\n" ); document.write( "\n" ); document.write( "(1/25-y^2)/(6-3y/y^2-7y+10)= ?\r
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Algebra.Com's Answer #153220 by PRMath(133)\"\" \"About 
You can put this solution on YOUR website!
\"%2815ab%2F4%29\"*\"%288%2F9a%5E2b%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "I won't know how to put this in nice fractions for you, so I'll explain, as best as I can, what I'm doing............\r
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\n" ); document.write( "\n" ); document.write( "\"%2815ab%2F4%29\"*\"%288%2F9a%5E2b%5E2%29\" \r
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\n" ); document.write( "\n" ); document.write( "The 15 and the 9 can each be reduced when divided by 3. They become 5 and 3.
\n" ); document.write( "The 4 and the 8 can each be reduced when divided by 4. They become 1 and 2
\n" ); document.write( "The ab in the numerator can be canceled, but that changes the \"a%5E2\" and the \"b%5E2\" in the denominator to: \"ab\"\r
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\n" ); document.write( "\n" ); document.write( "SO when we reduce and cancel, we get:\r
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\n" ); document.write( "\n" ); document.write( "\"%285%29%2A%282%29\"/\"%281%29%2A%283%29ab\" .........OR.........\r
\n" ); document.write( "\n" ); document.write( "\"10%2F3ab\"\r
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\n" ); document.write( "\n" ); document.write( "NEXT QUESTION:\r
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\n" ); document.write( "\n" ); document.write( "\"%286a%2F8b%29%2F%2810c%2F12d%29\" \r
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\n" ); document.write( "\n" ); document.write( "The above is how I am reading your question. If I am correct, then we would do that problem the way we would do any division problem when we work with fractions. In other words, when you divide with a fraction, you MULTIPLY by the reciprocal. So your problem is now........\r
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\n" ); document.write( "\n" ); document.write( "\"%286a%2F8b%29\"*\"%2812d%2F10c%29\"\r
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\n" ); document.write( "\n" ); document.write( "The 6 and the 10 can be reduced when divided by 2. They become 3 and 5.
\n" ); document.write( "The 12 and the 8 can be reduced when divided by 4. They become 3 and 2.\r
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\n" ); document.write( "\n" ); document.write( "Your problem is now............\r
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\n" ); document.write( "\n" ); document.write( "\"%283a%2F2b%29\"*\"%283d%2F5c%29\" and this is:\r
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\n" ); document.write( "\n" ); document.write( "\"9ad%2F10bc\"\r
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\n" ); document.write( "\n" ); document.write( "\"2x%5E2+%2B+x+-+3\"/\"9\"*\"%28x+%2B1%29%5E2\"/\"2x%5E2+%2B+5x+%2B+3\"\r
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\n" ); document.write( "\n" ); document.write( "If I have written your problem correctly, then it can be factored like this:\r
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\n" ); document.write( "\n" ); document.write( "\"%282x+%2B+3%29%28x-1%29%28x+%2B+1%29%28x+%2B+1%29\"/\"%289%29%282x+%2B+3%29%28x+%2B+1%29\"\r
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\n" ); document.write( "\n" ); document.write( "So the (2x + 3) in the numerator can be canceled with the (2x+3) in the denominator.
\n" ); document.write( "The (x + 1) in the numerator can be canceled with the (x + 1) in the denominator.\r
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\n" ); document.write( "\n" ); document.write( "That leaves you with:\r
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\n" ); document.write( "\n" ); document.write( "\"%28x+-+1%29%28x+%2B+1%29%2F9\"\r
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\n" ); document.write( "\n" ); document.write( "I am sorry to say that your last problem I don't think I'm seeing correctly. Can you repost it, please? It's this part of the problem I'm not sure about: \r
\n" ); document.write( "\n" ); document.write( "(1/25-y^2)\r
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\n" ); document.write( "\n" ); document.write( "I am not sure you have written it correctly. The second part is easily factored. The (6 - 3y) can be factored to 3(2 - y) and the \"y%5E2-7y%2B10\" can be easily factored to (y-5)(y-2). I just am not certain your first part of the problem is written correctly.\r
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\n" ); document.write( "\n" ); document.write( "I hope this helps .......
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