document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=203079>Question 203079</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The width of rectangle is 1 ft less than the length.  The area is 6ft^2.  find the lenght and the width.\r<BR>\n" );
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document.write( "width is 2 ft<BR>\n" );
document.write( "the length 3 ft.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #153206 by </B><A HREF=/tutors/aboutme.mpl?userid=dyakobovitch><B>dyakobovitch(40)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dyakobovitch><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=153206\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Width=L-1<BR>\n" );
document.write( "Length=L<BR>\n" );
document.write( "Area=LW=L(L-1)=6\r<BR>\n" );
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document.write( "L^2-L-6=0<BR>\n" );
document.write( "(L-3)(L+2)=0\r<BR>\n" );
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document.write( "So, L=3 [since -2 is an extraneous solution]<BR>\n" );
document.write( "By substitution, Width=L-1=3-1=2\r<BR>\n" );
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document.write( "--<BR>\n" );
document.write( "David </SPAN>\n" );
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